## Good news for a change

Sakineh Ashtiani is *free.*

Her release is a triumph for an intensive international campaign launched by her son Sajad Ghaderzadeh…Ecstatic campaigners hailed the news. “This is the happiest day in my life,” said Mina Ahadi of the International Committee against Stoning (Icas).

So maybe international pressure does work.

I’m pinching myself. Wow (if it really is what it seems to be).

great news, indeed.

Wow indeed.

[…] This post was mentioned on Twitter by Rational Humanist and Lucy Doig, Ophelia Benson. Ophelia Benson said: Good news for a change http://dlvr.it/B3vC7 […]

That’s absolutely fantastic news to hear. Gosh – it was also so close to being another tragic story to come out of Iran. I’ve been so dreadfully on tenterhooks about the whole issue. The unknowing was so utterly unnerving. I linked your stories here directly to indymedia Ireland and rateyoursolicitor all the time. So – it now gives me the greatest of pleasure to send the lastest link, with this nastonishing good news.

Sakineh Ashtiani isfree.I wish you all the best from Ireland, Sakineh. It’s so unfair why people like you get to suffer so much in your life. The decks of cards are laid out on ones lap, and there is no choice in the specific card one receives – called suffering. It’s all in the lap of the Gods. Sadly, you got, at firs,t such an unfair unlucky card. Nonetheless, you have now come up trumps with the second card you got – so there is now a lot to rejoice. Cheers!This is really hard to believe. Have we just passed through some sort of time warp? But let us not forget the ten women and four men who have been sentenced to death by stoning, and are still waiting to die.

And let us not forget that people are still executed regularly in the United States and elsewhere, that the system in the US is laced with racism, and that, inevitably, innocent people are also killed. Justice William Brennan said, in 1987:

As Justice Thurgood Marshall said in 1990, when the US Supreme Court, in Gregg v. Georgia

Sadly, Ahmadinajad’s reference to Teresa Lewis, if not genuinely a parallel to the case of Sakineh Ashtiani, is too close for comfort. According to DSM-IV mild mental retardation ranges from IQ 50-55-70. Teresa Lewis’s verbal IQ was 70. She had a performance IQ of 79. The man chiefly responsible for the murders had an IQ of 119, and was clearly in charge. If questions of justice are at issue, the US must look to its practice of capital punishment, a system which is seriously skewed and unjust. I do not defend Iran or its government, but, on this occasion, they seem to have effectively brought attention to a systemic injustice in the American justice system.

Thank you, Eric, you are perfectly right. I remember a case many many years ago when an American court, despite all our appeals, executed a mentally subnormal man for a crime he hardly had the brains to commit. There is no possible remedy for the crime of lawfully killing an innocent person. Better that Hitler should live on in prison than that an innocent person should be eternally removed from existence by law.

Oh well, the good news is, Sakineh is saved. I hope it’s true.

It looks as if it’s not true. Bastards.

http://edition.cnn.com/2010/WORLD/meast/12/09/iran.stoning.photographs/

Well, it did sound too good to be true, didn’t it? I still think the US should reconsider its capital punishment policy, but if they have not released Ashtiani, then it was not Iran that brought attention to it. However, it has been flying under the radar for too long.

Oh, I think the US should dump capital punishment too.

We’re a hateful country in so many ways. No you may not have progressive taxation; no you may not have a National Health; no you may not have an equal rights amendment; no you may not have a repudiation of the death penalty; no you may not have gays in the military.

Y=abx

B influences vertical curve of the line. It influences the curve by a factor of a multiplied by b when x increases by 1.

If a is positive and

• When b more than 0 the line curves upward in Quadrant 1

• When b is less than 0 it is a reflection on the x axis of the additive inverse of b that goes vertically downward from q3 to q4

• When b =0 the line is a horizontally straight line of the x axis except when x=0. There is no answer for when y=00

If a is negative and

• B is more than 0 the line is in Q4 and slopes vertically downward into Q3.

• B is less than 0 it is a reflection of when b is greater than zero. It is in q1and q2 and moves upward vertically.

• When b=0 the line is horizontal on the x axis with a break in the graph at 0 due to the fact that 00 is nonreal number.

The value of x determines the vertically parabola of the line. The vertical value of the line increases exponentially when the value of x increases.

Y=ab-x

The exponent of –x makes the line asymptote where the line gets closer to but never touches the x axis as x decreases. The line is divided by (a multiplied by b) when x decreases by one.

If a is positive and

• B is more than 0 the line curves downward vertically as x decreases from Q2 to Q1.

• B is less than 0 than the line is a reflection on the x axis of the additive inverse of b. This line curves upward towards the x axis as x decreases from Q3 to Q4

• When b=0 the line is horizontal across the x axis accept.

If a is negative and

• B is more than 0 the line is in Q3 and Q4 and is a reflection on the x axis of the additive inverse of b.

• B is less than 0 the line is in Q2 and Q1 and is a reflection on the x axis of the additive inverse of –b.

• B is =0 then it is a horizontal line on the x axis.

Y=a1/bx is a reflection of y=ab-x on the y axis.

Therefore

The exponent of x makes the line asymptote where the line gets closer to but never touches the x axis as x increases in Q1. The line is divided by (a multiplied by b) for each increase of 1 for x.

If a is positive

• B is more than 0 the line is in Q3 is a reflection on the x axis of the additive inverse of b.

• B is less than 0 the line is in Q2 and is a reflection on the x axis of the additive inverse of –b.

• B is =0 then it is a horizontal line on the x axis.

If a is negative

• B is more than 0 the line curves downward vertically as x increases in from Q2 to Quadrant 1.

• B is less than 0 than the line is a reflection on the x axis of the additive inverse of b. This line curves downward towards the x axis as x increases. It is from Q3 to Q4.

• When b=0 the line is horizontal across the x axis accept.

Y=abx+c

The value of c creates a vertical shift upward to the value of c off the line on the y axis. If c is negative there is a vertical shift downward of the value of –c of the line on the y axis. B and a influences vertical curve of the line. It influences the curve by a factor of a multiplied by b when x increases by 1. The vertical value of the line increases exponentially when the value of x increases.

When x is greater than or equal to 0 and

If a is positive and

• When b more than 0 the line curves upward in Quadrant 1

• When b is less than 0 it is a reflection on the x axis of the additive inverse of b that goes vertically downward in Quadrant 4

• When b =0 the line is a horizontally straight line of the x axis except when x=0. There is no answer for when y=00

If a is negative and

• B is more than 0 the line is in Q4 and slopes vertically downward

• B is less than 0 it is a reflection of when b is greater than zero. It is in q1 and moves upward vertically.

• When b=0 the line is horizontal on the x axis with a break in the graph at 0 due to the fact that 00 is nonreal number.

When x is less than 0

The exponent of –x makes the line asymptote where the line gets closer to but never touches the x axis as x decreases. The line is divided by (a multiplied by b) when x decreases by one.

If a is positive and

• B is more than 0 the line curves downward vertically as x decreases in Quadrant 2.

• B is less than 0 than the line is a reflection on the x axis of the additive inverse of b. This line curves upward towards the x axis as x decreases.

• When b=0 the line is horizontal across the x axis accept.

If a is negative and

• B is more than 0 the line is in Q3 is a reflection on the x axis of the additive inverse of b.

• B is less than 0 the line is in Q2 and is a reflection on the x axis of the additive inverse of –b.

• B is =0 then it is a horizontal line on the x axis.

When the equation has 1/b instead of b

The exponent of x makes the line asymptote where the line gets closer to but never touches the x axis as x increases in Q1. The line is divided by (a multiplied by b) for each increase of 1 for x.

If a is positive

• B is more than 0 the line is in Q3 is a reflection on the x axis of the additive inverse of b.

• B is less than 0 the line is in Q2 and is a reflection on the x axis of the additive inverse of –b.

• B is =0 then it is a horizontal line on the x axis.

If a is negative

• B is more than 0 the line curves downward vertically as x increases in from Q2 to Quadrant 1.

• B is less than 0 than the line is a reflection on the x axis of the additive inverse of b. This line curves downward towards the x axis as x increases. It is from Q3 to Q4.

• When b=0 the line is horizontal across the x axis accept.

Bryan White

12/18/10

Mrs. Wiley Algebra 2

6-4 Writing Assignment

When observing the functions y=abx, y=ab-x, y=a1/b x, and y=abx, the values of a, b, and c determine the position, slope, and reflections of their corresponding graphs.

When y=abx, the values of a and b influence the line. When the values of a and b are greater than 0, the line is more vertical by a factor of b when the value of x increases by 1. The line is in Quadrant 1 when b and a are greater than zero. The value of x determines the exponential increase of the graph. When b is less than zero and a is positive or when a is negative and b is positive, there is a reflection of b and its additive inverse over the x axis. This line is in Quadrant 4. When either b or a is equal to 0 the line is horizontal on the x axis. If b and x is 0 the line is horizontal on the x axis with a break at 0 since 00 is an undefined number. When neither a nor b is 0 and x is 0 the equation is y=a. In fig 1, the equation y=2·3x the line is in Quadrant 1 and curves upward vertically. The value of y is 6 times greater than the previous value of y. Therefore when the value of x increases by 1, the value of y is multiplied by 2·3 or 6.In fig. 2 the equation graphed is 0·5x. The line is horizontal on the x axis due to a being 0. In fig. 3 the equation graphed is 5·0x. This equation is horizontal on the x axis with a break at 0. In fig. 4 the equation graphed is -2·3x. This equation is a reflection of fig. 1 and decreases by a factor of 6 in Quadrant 4. Fig. 5 is the equation is y=5·0x , the line is horizontal at the y value of 5.

When y=ab-x, the value a and b influence the line. This line is an asymptote where as the x value decreases the y value decreases and comes close to but never touches the x axis. This line is in Q2 when a and b are positive or when a and b are both negative. When one of the two variables is negative and the other is positive the line is in Quadrant 3. When an additive inverse is substituted in one of these equations for a or b it creates a reflection over the x axis of the original equation. The line is more vertical by a factor of the absolute value of (b) for each increase of 1 for x. Therefore when abx is in Quadrant 4 it will curve downward vertically. When a and b are positive the equation will curve upward vertically. When a is 0 then the line is horizontal on the x axis. When b is 0 there is no graph since 0 to the power of a negative number is a nonreal answer. In fig. 6 the equation shown is y=3·2-x. This line is in Quadrant 2 and increases by a factor of 1/6 for each decrease of one for x. In fig. 7 y=-3·2-x the line is in Quadrant 3 and is a reflection of fig. 6. It goes upward vertically by a factor 1/6 for each decrease of 1 for x. In fig. 8 the equation shown is y=0·5-x. This equation is a horizontal line on the x axis.

The equation (y=a 1/b x) is as reflection of the y=ab-x over the y axis when the values of a and b are the same. Therefore when a and b are both negative or positive then the line is an asymptote in Quadrant 1. The line gets closer to the x axis as the value of x increases. When a or b is negative the line is in Quadrant 4. When b is 0 the line is horizontal on the x axis. The lines for this equation are asymptotes. In fig. 9 the equation show is y=5·1/10 x the line is in Quadrant 1 and decreases exponentially when the value of x increases by 1. In fig. 10 the equation shown is y=-4·1/12 x . This equation is in Quadrant 4 and increases exponentially towards the x axis but since it is asymptote it never reaches it.

When y=abx+c, the value of c creates a vertical shift upward to the value of c off the line on the y axis. The value of a shifts the line up by a factor of a. If c is negative there is a vertical shift downward of the value of –c of the line on the y axis. B and a influences vertical curve of the line. It influences the curve by a factor of a multiplied by b when x increases by 1. The vertical value of the line increases exponentially when the value of x increases. When a and b are both negative or positive the line lies in Quadrant 1 and 2. This line is asymptote and increases by a factor of b for each increase of 1 for the value of x. When a or b is negative and the line lies in Quadrant 3 and 4.When b is equal to 0 it creates a horizontal line on the x axis with a break at the origin since 00 is not a real number. When 1/b is substituted for b the line becomes the reflection of y=ab-x. In fig. 11the equation shown is -4·5x . The line is in Quadrant 4 and the line increases by a factor of 5 for each increase of 1 for x. In fig.12 the equation shown is y=4·5x. This line is in Quadrant 1 and is a reflection of fig. 11. In fig. 13 the equation is y=2·1/4x +5. This equation is asymptote that gets close to but never touches the y value of 5 since there was a vertically shift of 5 upward on the y axis. In fig. 14 the equation shown is 2·4-x+5. This equation is a reflection of fig. 13 over the y axis. In the equation y=0·5x-2, the line is horizontal and experiences a vertical shift downward of -2.

The values of a, b, and c change the lines of the graphs from the equations y=abx, y=ab-x, y=a1/b x, and y=abx. The value of c affects the vertical shift of the line on the y axis. The value of a makes the line have a vertical shift of the factor of a. The variable b makes the line of these functions more vertical or more horizontal depending on the value of b.